Question

What is the resulting temperature when 150g of ice st 0℃ is mixed with 300g of water at 50℃?

Answer 1

hyy here is your answer ⤵️

➡️ 150(80 + T) = 300(50 - T)

➡️ 12000 + 150 T = 15000 -300 T

➡️ 450 T = 3000

$T \: = \frac{3000}{450}$


➡️ T = 6.6 ° Celsius.

✴️ hence, 6.6°Celsius is the resulting temperature when 150g of ice at 0°c is mixed with 300g of water at 50°c.

____hope it help ✌️

Answer 2

0°C ice to 0°C water

Q1= mL=150×80=12000cal

Water at 50°C to water at 0°C

Q2=mc∆T = 300×1×50=15000cal

Q2>Q1 = whole ice is converted into water

Net water =300+150=450g

rise in temperature

Q=mc∆T

3000=450×1×∆T

∆T= 3000/450=6.7°C