what is the retardation, if a car moving with a velocityof 50km/hr is brought to rest in45 sec?
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Answered by
1
a=(Vf-Vi) /t
=( 0-50*1000)/45
=-10000/9 m/s^2
Answered by
3
Answer:
Given that;
Initial velocity ( u) = 50km/ h
converting km/ h into m/ s
u = 5*(5/18)
u =13•88m/s
Final velocity ( v) = 0m/ s
Time taken ( t) = 45s
Retardation (-a) = ?
We know that,
a =( v-u)/t
a= ( 0-13•88 ) /45
a=-13•88/45
a= -0•308 m/ s
-a = 0•308 m/ s
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