Question

what is the root of 12345654321

Answer 1

since the sum of digits 12345654321 is divisible by 3 -> its square root also should have the sum of digits divisble by 3 -> B,D outA is out because last digit can't be 2 because 2^2 = 4 -> A is outC is divisible by 11 (E is not) check the number12345654321 is divisible by 11 -> C is correct

Answer 2

Answer:

your correct answer is

$\sqrt{12345654321}$

$111111 {}^{2}$

Step-by-step explanation:

i will show you how to do this root very easily.

see the number- 12345654321

the biggest digit is 6 in this problem

so , the answer will be six 1 {111111}

other examples -

√123454321

in this case also same rule

the greatest digit is 5

so, five 1 ( 11111)

Note-

this rule only occurs in this type of sums

√12345678987654321 = 111111111

√123456787654321 = 11111111

√1234567654321 = 1111111

√12345654321 = 111111

√123454321 = 11111

√1234321 = 1111

√12321 = 111

√121 = 11

I am absolutely right. that I am sure

you can see the answer also in calculator