Question

What is the roots of quadratic equation 21x^2-37x-28=0?

Answer 1

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$= > \bf \: 21 {x}^{2} - 37x - 28 = 0 \\ \\ = > 21 {x}^{2} - 49x + 12x - 28 = 0 \\ \\ = > 7x(3x - 7) + 4(3x - 7) = 0 \\ \\ = > (7x + 4)(3x - 7) = 0 \\ \\ \bf \underline{either} \\ \\ = > 7x + 4 = 0 \\ \\ = > \bf \: x = \frac{7}{4} \\ \\ \bf \underline{or} \\ \\ = > 3x - 7 = 0 \\ \\ = > \bf \: x = \frac{7}{3}$
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