Question

What is the rotational kinetic energy of a 60cm diameter bicycle wheel of mass 4.0kg
when the bicycle is travelling at 4.0m/s. Take the radius of gyration k = 50?

Answer 1

Theory :-

Kinetic energy of rotation, K.Eᵣ = (1/2)Iω²

Moment of inertia, I = mk²

Angular velocity, ω = (V/R)

where,

k = Radius of gyration

R = Radius of the trajectory

V = Linear velocity

m = Mass of the body

Solution :-

Putting given values in mentioned formulas

We get,

I = (4.0)(0.50)² = 1 kgm²

ω = (4.0/0.30) = (40/3) rads⁻¹

So, KEᵣ = (1/2) × (1) × (40/3)²

= 88.88 Joules

≈ 89 Joules

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