Question

What is the rpm of the last driven pulley, if a motor runs at 1440 revolutions /min is connected by means of a multiple belt drive and the individual transmission ratios are 3:2,4:1?​

Answer 1

Dear Student,

◆ Answer -

8640 rpm

◆ Explanation -

Pet f1, f2 and f3 be rpm of motor, 1st pulley and 2nd pulley.

From given data,

f2/f1 = 3/2

f2/1440 = 3/2

f2 = 1440 × 3/2

f2 = 2160 rpm

Also,

f3/f2 = 4/1

f3/2160 = 4

f3 = 2160×4

f3 = 8640 rpm

Therefore, rpm of last driven pulley must be 8640 rpm.

Thanks dear...

Answer 2

Answer:

what is answer, something rong answer.