What is the rtatio of distance travelled by a body falling freely from rest in 1st 2nd and 3rd second
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Distance travelled in 'n'th second-
S=u+a/2×{2n-1}
distance travelled in first second-
S'=0+10/2×{(2+1)-1}
S'=5
distance travelled in second second-
S"=0+10/2×{(2×2)-1}
S"=15
distance travelled in third second-
S"'=0+10/2×{(2×3)-1}
S"'=25
So,
S':S":S"'=5:15:25=1:3:5
S=u+a/2×{2n-1}
distance travelled in first second-
S'=0+10/2×{(2+1)-1}
S'=5
distance travelled in second second-
S"=0+10/2×{(2×2)-1}
S"=15
distance travelled in third second-
S"'=0+10/2×{(2×3)-1}
S"'=25
So,
S':S":S"'=5:15:25=1:3:5
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