what is the S7 of the terms in the AP 1.0, 1.5, 2.0, 2.5?
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First term=a=1
Common difference d=0.5
Sum of n terms=n/2(2a+(n-1)d
Sum of 7 terms =7/2(2+6*0.5)=17.5
Common difference d=0.5
Sum of n terms=n/2(2a+(n-1)d
Sum of 7 terms =7/2(2+6*0.5)=17.5
Answered by
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HOLA USER ✌
HERE'S YOUR ANSWER FRIEND,
GIVEN : ARITHMETIC PROGRESSION
==> 1 , 1.5, 2, 2.5
LET a BE THE FIRST TERM AND d BE THE COMMON DIFFERENCE AND L be the LAST TERM.
HERE, a = 1, d = 1.5 - 1 = 0.5
WE KNOW,
Sn = n/2(2a + (n -1)d)
HERE
n( no.of terms = 7)
==> S7 = 7/2(2(1) + (7 -1)0.5)
==> S7 = (3.5)(5)
==> S7 = 17.5
HOPE IT HELPS YOU.
HERE'S YOUR ANSWER FRIEND,
GIVEN : ARITHMETIC PROGRESSION
==> 1 , 1.5, 2, 2.5
LET a BE THE FIRST TERM AND d BE THE COMMON DIFFERENCE AND L be the LAST TERM.
HERE, a = 1, d = 1.5 - 1 = 0.5
WE KNOW,
Sn = n/2(2a + (n -1)d)
HERE
n( no.of terms = 7)
==> S7 = 7/2(2(1) + (7 -1)0.5)
==> S7 = (3.5)(5)
==> S7 = 17.5
HOPE IT HELPS YOU.
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