Physics, asked by devansu3806, 10 months ago

What is the second equation of motion for a body projected vertically upwards?

Answers

Answered by Iamkeetarp
0

s = ut - gt^2/2

Hope it helped you

Answered by Anonymous
15

Answer:

s= 1/2 at^2

=Distance travelled by object= area of trapezium (OABC)

=Area of OADC ( rectangle)+ area of ABD (triangle)

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