Question

What is the sequence of An=2n-1

Answer 1

Given sequence is $\large\rm { A_{n} = 2n-1}$

The first term $\large\rm { A_{1} }$ can be determined by substituting n=1 in the sequence $\large\rm { A_{n} = 2n-1}$ as follows:

$\large\rm { t_{1} = (2×1) - 1 = 1}$

The second term $\large\rm { A_{2} }$ can be determined by substituting n=1 in the sequence $\large\rm { A_{n} = 2n-1}$ as follows:

$\large\rm { t_{2} = (2×2) - 1 = 3 }$

The third term $\large\rm { A_{3} }$ can be determined by substituting n=1 in the sequence $\large\rm { A_{n} = 2n-1}$ as follows:

$\large\rm { t_{3} = (2×3) - 1 = 5}$

Hence, the sequence is $\large\rm { 1,3,5,........ \infty }$

Answer 2

• Step-by-step explanation:
• Given sequence is \large\rm { A_{n} = 2n-1}A
• n
• =2n−1
• The first term \large\rm { A_{1} }A
• 1
• can be determined by substituting n=1 in the sequence \large\rm { A_{n} = 2n-1}A
• n
• =2n−1 as follows:
• \large\rm { t_{1} = (2×1) - 1 = 1}t
• 1
• =(2×1)−1=1
• The second term \large\rm { A_{2} }A
• 2
• can be determined by substituting n=1 in the sequence \large\rm { A_{n} = 2n-1}A
• n
• =2n−1 as follows:
• \large\rm { t_{2} = (2×2) - 1 = 3 }t
• 2
• =(2×2)−1=3
• The third term \large\rm { A_{3} }A
• 3
• can be determined by substituting n=1 in the sequence \large\rm { A_{n} = 2n-1}A
• n
• =2n−1 as follows:
• \large\rm { t_{3} = (2×3) - 1 = 5}t
• 3
• =(2×3)−1=5
• Hence, the sequence is \large\rm { 1,3,5,........ \infty }1,3,5,........∞