what is the sequence x{n} into
a sum of weighted impulse sequences
if x(n) ={2, 4,0,3}
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Answer: b
Explanation: We know that, x(n)δ(n-k)=x(k)δ(n-k)
x(-1)=2=2δ(n+1)
x(0)=4=4δ(n)
x(2)=3=3δ(n-2)
Therefore, x(n)= 2δ(n+1)+4δ(n)+3δ(n-2).
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