Math, asked by Luciferreloaded, 9 months ago

What is the set builder form of the set A={1,4,9,16,25,36,49,64,81,100} and
B={6,12,18,24,30,36,42,48} . Please Give answer in both numericals (symbol, numbers, alphabets ) and in words/sentences.

Answers

Answered by mansipatel2966
2

A= {x/x=a^2, a belongs N, a<11}

B= {x/x is a multiple of 6 and x<50}

Answered by hipsterizedoll410
2

Answer: A={x:x = n², where n∈ N and 1≤n≤10  } where N is the set of natural numbers.

B={x:x = 6n where n∈ N and  1≤n≤8}

Step-by-step explanation:

Given that,

A = {1,4,9,16,25,36,49,64,81,100}

As we can see that it is the perfect squares of natural numbers from 1 to 10. So, in set builder form it can be written as,

A={x:x is a square of a natural number where 1≤x≤10}

                 OR

A={x:x = n², where n∈ N and 1≤n≤10  } where N is the set of natural numbers.

It can be read as," x such that x = n² where n belongs to the set of natural numbers where n lies between 1 to 10 "

B={6,12,18,24,30,36,42,48}

Here we can see that, it is the multiple of 6 till 8 so,

B={x:x is a multiple of 6 where 1≤x≤8}

              OR

B={x:x = 6n where n∈ N and  1≤n≤8}

It can be read as, " x such that x=6n, where n belongs to the set of natural numbers and n lies between 1 to 8."

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