Question

What is the shortest wavelength line in the Balmer series of Be+3 ion is (RH = Rydberg constant)?

Answer 1

GIven :

Rydberg constant = RH

Ion = B$e^{+3}$

To find :

The shortest wavelength line in the Balmer series .

Solution :

1/λ = RH * z * z $($ $\frac{1}{n_1 ^ {2}} - \frac{1}{n_2 ^ {2}}$ $)$

where , z is the atomic number ,

$n_1$ = 2 for balmer series ,

and , $n_2$ = ∞ for shortest wavelength

now ,

1/λ = RH * 4 * 4 * ( 1/4 )

=> 1/λ = 4 RH

=> λ = 1 / 4 RH

The shortest wavelength line in the Balmer series of B$e^{+3}$ ion is 1 / 4 RH .