Question

what is the shortest wavelength present in the paschen series of spectral lines ?​

Answer 1

Answer:

107 m-1.

What is the shortest wavelength present in the Paschen series of spectral lines? 107 m-1. , is the value of the shortest wavelength.

Answer 2

Answer:

• 818.9 nm

Explanation:

The Rydberg’s formula is

$\boxed{hc/\lambda= 21.76 \times 10^{-19} [1/(n_{1})^{2} -1/(n_{2})^{2}]}$

Where,

• h = Planck’s constant (66 × 10$^{-34}$Js)
• c = Speed of light (6.6 × 10$^{8}$m/s)
• n$_{1}$ & n$_{2}$ = integers

By Paschen series, Shortest wavelength of the spectral linesis given for values

• n$_{1}$ = 3
• n$_{2}$ = $\infty$

$\implies\:\: hc/\lambda = 21.76 \times 10^{-19} [1/(3)^{2} -1/(\infty)^{2}]$

$\implies\:\:\lambda =6.6 \times 10^{-34} \times 3\times 10^{8} \times 9/21.76\times 10^{-19}$

$\implies\:\:\lambda = 8.189 \times 10^{-7} m$

$\implies\:\:\boxed{\lambda = 818.9 \:nm}$