Science, asked by atulyapatel636, 2 months ago

What is the significance of the transpiration process in plants?​

Answers

Answered by pgpc
2

The process of transpiration keeps the cell turgid, cools the surface of the leaves, and helps in the movement of minerals from the soil to different parts of the plant.

Answered by gamerzc014
0

Answer:

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

⟹450=

2

1

(20+b)×15

:⟹450×2=(20+b)×15

:⟹900=(20+b)×15

:⟹900=300+15b

:⟹900−300=15b

:⟹600=15b

:⟹b=

15

600

:⟹

b=40m

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