Question

what is the simple interest earned over a period of six years on a principal of ₹20000at a rate of 5% per annum​

Answer 1

$\large\underline{\sf{Solution-}}$

Given that,

Principal, P = ₹ 20000

Rate of interest, r = 5 % per annum

Time, n = 6 years

We know,

Simple interest (SI) received on a certain sum of money of ₹ P invested at the rate of r % per annum for n years is given by

$\color{green}\boxed{ \rm{ \:SI \: = \: \frac{P \: \times \: r \: \times \: t}{100} \: \: }}$

So, on substituting the values, we get

$\rm \: SI \: = \: \dfrac{20000 \times 5 \times 6}{100}$

$\rm \: SI = 200 \times 30$

$\rm\implies \:SI \: = \: 6000$

Hence,

Simple interest earned over a period of six years on a principal of ₹20000at a rate of 5% per annum is ₹ 6000.

$\rule{190pt}{2pt}$

Additional Information :-

$\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{P = \dfrac{SI \times 100}{r \times n} }\\ \\ \bigstar \: \bf{r = \dfrac{SI \times 100}{P \times n} }\\ \\ \bigstar \: \bf{n = \dfrac{SI \times 100}{P \times r} }\\ \\ \bigstar \: \bf{Amount = P\bigg(\dfrac{100 + rn}{100} \bigg) }\: \end{array} }}\end{gathered}\end{gathered}\end{gathered}$

Answer 2

QUESTION :-

what is the simple interest earned over a period of six years on a principal of ₹20000 at a rate of 5% per annum

GIVEN :-

six years on a principal of ₹20000at a rate of 5% per annum

TO FIND :-

what is the simple interest = ?

SOLUTION :-

SI = P × T × R / 100

putting the value we get :

= 20000 × 6 × 5 / 100

= 6000

simple interest = rs 6000