Question

What is the simplest approach to get factors of any quadratic equation?​

Answer 1

Step-by-step explanation:

factor a quadratic, we'll need to start by finding the two numbers (being the p and the q above) that add up to equal b, where those numbers also multiply to equal c. It's required by the logic of factoring (and factoring the quadratic is the "undo" of the original binomial multiplication).

(By the way, I call this topic "factoring quadratics", where your textbook may refer to this topic as "factoring trinomials". But a "trinomial" is any three-term polynomial, which may not be a quadratic (that is, a degree-two) polynomial. And not all quadratics have three terms. So the book's section or chapter title is, at best, a bit off-target. Don't worry about the difference, though; the book's title means the same thing as what this lesson explains.)

hope will help you

Answer 2

Step-by-step explanation:

There are many ways to factorise quadratic equations.

let the quadratic equation be ax²+bx+c

1. Multiply a and c then find the L.C.M. of the product. After this find the ways to do sum of the multiples to get b. After doing this take common between first two and last two and then take one common between them.
2. firstly find the value of x by the formula (-b±√(b²-4ac))/2a. You will get answer. Let the two answer be s and t. Then factorise by writing (x-s)(x-t).

Between these two 2nd one is very simple but you have to learn the formula (-b±√(b²-4ac))/2a