Question

What is the simplified form of (2b2 – 6) + (4b + 7) – (b2 + 5b – 3)?

Answer 1

$Given \: (2b^{2} -6)+(4b+7)-(b^{2} + 5b-3)$

$= 2b^{2} -6+4b+7-b^{2} - 5b+3$

/* Rearranging the terms , we get */

$= 2b^{2} - b^{2} +4b-5b-6+3$

$= (2-1)b^{2} + (4-5)b - 3$

$= b^{2} - b - 3$

Therefore.,

$\red{(2b^{2} -6)+(4b+7)-(b^{2} + 5b-3)}$

$\green { = b^{2} - b - 3 }$

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