Physics, asked by sujith214, 4 months ago

What is the size of image if the object is placed beyond pole in convex mirror?​

Answers

Answered by Saad390
1

Answer:

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Answered by Laraleorapathi
0

Explanation:

a) For a concave mirror, the focal length (f) is negative.

When the object is placed on the left side of the mirror, the object distance (u) is negative

For image distance v we can write

v

1

+

u

1

=

f

1

v

1

=

f

1

u

1

...(1)

The object lies between f and 2f.

2f<u<f

2f

1

>

u

1

>

f

1

2f

−1

<

u

−1

<

f

−1

f

1

2f

1

<

f

1

u

1

.......(2)

from eq. 1

2f

1

<

v

1

<0 ; v is negative

2f>v

−v>−2f

Therefore, the image lies beyond 2f.

b) For a convex mirror, the focal length (f) is positive

When the object is placed on the left side of the mirror, the object distance (u) is negative

For image distance v, we have the mirror formula

v

1

+

u

1

=

f

1

v

1

=

f

1

u

1

Using eq (2)

v

1

<0

v>0

Thus, the image is formed on the back side of the mirror.

Hence, a convex mirror always produces a virtual image, regardless of the object distance.

c) For a convex mirror, the focal length (f) is positive

When the object is placed on the left side of the mirror, the object distance (u) is negative

For image distance v, we have the mirror formula

v

1

+

u

1

=

f

1

v

1

=

f

1

u

1

but u<0

therefore

v

1

>

f

1

v<f

Hence, the image formed is diminished and is located between the focus (f) and the pole

d) For a concave mirror, the focal length (f) is negative

When the object is placed on the left side of the mirror, the object distance (u) is negative

It is placed between the focus (f) and the pole

therefore f>u>0

f

1

<

u

1

<0

f

1

u

1

For image distance v, we have the mirror formula

v

1

+

u

1

=

f

1

v

1

=

f

1

u

1

v

1

<0

v>0

The image is formed on the right side of the mirror. Hence, it is a virtual image

For u<0 and v>0, we can write:

u

1

>

v

1

so v>u

magnification m=

u

v

>1

Hence, the formed image is enlarged.

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