Question

What is the size of the array in the code shown below.(Assume l character occupies 1 byte)
typedef char a[10];
a myarray[5];
Select one:
A. 10 bytes
B. 40 bytes
C.50 bytes
D.5 bytes​

Answer 1

Answer:

50 bytes

Step-by-step explanation:

1 byte for character

a[10] -- 10 bytes

myarray[5] --- 5*10 = 50 bytes

Answer 2

Concept: A group of items kept in consecutive memory regions is known as an array. The goal is to group objects of the same category for storage. As a result, it is simpler to determine each element's position by simply adding an offset to a base value, or the address in memory where the array's first element is stored (generally denoted by the name of the array). Index 0 serves as the basis value, and the offset is the difference between the two indices.

Given: the code

typedef char a[10];

a myarray[5];

To find: the size of the array

Solution: myarray will have a size of 50 bytes. The character array x, which is 10 characters long, has been defined in the code above. As a result, the code's output is 10 * 5, or 50 bytes.

Hence, the size of the array is 50 bytes.

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