Question

what is the size of the image when
the object is placed as shown in figure​

Answer 1

From the figure

μ

1

=1,μ

2

=1.33,u=−40cm,R=−20cm (by sign convention)

Substituting the given values in the above formula, we get

v

1.33

−

40

−1

=−

20

1.33−1

Solving, we get v=32.05cm

Magnification m=

1.33

1

×

40

32.05

=0.6

Height of the object is 1cm

Therefore height of the image is 1×0.6=0.6cm

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