Question

What is the slant height of cone if the total surface area of cone is 17776 meter cube and the radius of cone is 56 m.?​

Answer 1

Answer:

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Answer 2

Given :

• TSA of cone = 17776 m²
• Radius of cone = 56 m

To Find :

• Slant height $\sf (\ell)$ of the cone = ?

Solution :

We know that,

$\large \underline{\boxed{\bf{TSA = \pi r (l+r)}}}$

By substituting values, and take π = $\sf \dfrac{22}{7}$

$\sf : \implies 17776 = \dfrac{22}{\cancel{7}} \times \cancel{56} ( \ell + 56)$

$\sf : \implies 17776 = 22 \times (8 \ell + 448)$

$\sf : \implies \cancel\dfrac{17776}{22} = 8 \ell + 448$

$\sf : \implies 808 = 8 \ell + 448$

$\sf : \implies 808-448 = 8 \ell$

$\sf : \implies 360 = 8 \ell$

$\sf : \implies \cancel\dfrac{360}{8} = \ell$

$\sf : \implies 45 = \ell$

Hence, Slant height $\sf (\ell)$ of cone = 45 m.