Question

What is the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5?

A.y = x – 8
B.y = x + 1
C.y = x + 1
D.y = x + 10

Answer 1

Answer:

y = $\frac{3}{2}$ x + 10

Step-by-step explanation:

2x + 3y = - 5 ⇔ y = - $\frac{2}{3}$ x - $\frac{5}{3}$  

m = - $\frac{2}{3}$

The slope of ⊥ line is $\frac{3}{2}$

y - 1 = $\frac{3}{2}$ (x + 6) ⇔ y = $\frac{3}{2}$ x + 10