What is the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5?
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Step-by-step explanation:
2x + 3y = - 5
It is perpendicular to to 2x+3y=-5
Lets first find slope of this equation.
y=-2x/3–5/3
We know y=mx+c
m=-2/3
Since the first line is perpendicular to the above equation.
m1*m2=-1
m2=-1/m1
m2=3/2
So equation of your line is
y-y1=m(x-x1)
where (x1,y1)=(-6,1)
y-1=3/2(x+6)
2y-2=3x+18
3x-2y+20=0
Thus your equation is 3x-2y+20=0
hope it help
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