What is the slope of a line perpendicular to 2y=−6x−10?
Answers
Answered by
2
Solution:
Given equation of a straight line:
2y = -6x-10
divide each term by 2 , we get
=> y = -3x-5
=> y = (-3)x+(-5) Compare this
with y = mx+c , we get.
slope of a line (m) = -3
Now ,
slope of a line perpendicular to
the given line = -1/m
= -1/(-3)
= 1/3
••••
Answered by
0
Answer:
Step-by-step explanation:
Attachments:
Similar questions