What is the slope of a line perpendicular to 3x – 7y + 2 = 0? Explain.
Answers
Step-by-step explanation:
This equation is in standard form. The standard form of a linear equation is: Ax+By=C
Where, if at all possible, A, B, and Care integers, and A is non-negative, and, A, B, and C have no common factors other than 1.
The slope of an equation in standard form is: m=−AB
Therefore the slope of 3x−7y=−2 can be found by substituting as follows:
m=−3−7=37
The slope of a line perpendicular to the line in the problem (let's call it mp) will have a slope which is the negative inverse or:
mp=−73
Step-by-step explanation:
This equation is in standard form. The standard form of a linear equation is:
A
x
+
B
y
=
C
Where, if at all possible,
A
,
B
, and
C
are integers, and A is non-negative, and, A, B, and C have no common factors other than 1.
The slope of an equation in standard form is:
m
=
−
A
B
Therefore the slope of
3
x
−
7
y
=
−
2
can be found by substituting as follows:
m
=
−
3
−
7
=
3
7
The slope of a line perpendicular to the line in the problem (let's call it
m
p
) will have a slope which is the negative inverse or:
m
p
=
−
7
3