Question

what is the slope of a line perpendicular to the line 3x=4y+11​

Answer 1

I hope you understood from pic

Answer 2

Answer:

Slope of the line  = $-\frac{4}{3}$  

Step-by-step explanation:

Given line is  3x=4y+11

given line can be written as  4y = 3x - 11

                                               $y = (\frac{3 }{4} )x - \frac{11}{4}$ _(1)

∴ slope of line (1)  m₁ = $\frac{3}{4}$    

here we need to find slope of a line which is perpendicular to line (1)  

Let m₂ be the slope of the line which is perpendicular to line (1)

As we know that product of slopes of two perpendicular lines = -1

then     m₁m₂ = - 1

           $\frac{3}{4} (m_{2}) = -1$  

            3m₂ = - 4

              m₂ = $-\frac{4}{3}$