Question

what is the slope of curve of x^2 + 3x -29x^3 at x = 5?

Answer 1

Answer:

-2162

Step-by-step explanation:

slope can be calculated as

dy/dx

slope = $\frac{d(x^{2} + 3x - 29^{3}) }{dx}$

          = $2x + 3 -87x^{2}$

at x = 5

slope = $2(5) + 3 -87(5)^{2}$

          = 10 + 3 - 2175

          = -2162

Answer 2

Answer:

-2162

Step-by-step explanation:

do dydx

and put x = t in dy/dx