Question

What is the slope of the line that contains ( 8, 1) and (-2, 3)? Write your answer as m=

Answer 1

GIVEN :–

• A line contain two points are (8,1) and (-2,3).

TO FIND :–

• Slope(M) of line = ?

SOLUTION :–

• We know that –

$\\ \large \implies{ \boxed{ \bf \: Slope(M) = \dfrac{ y_{2} -y_{1}}{x_{2} -x_{1}}}}$

• Here –

$\\ \bf \: \: {\huge{.}} \: \: \: x_{1} = 8$

$\\ \bf \: \: {\huge{.}} \: \: \: x_{2} = -2$

$\\ \bf \: \: {\huge{.}} \: \: \: y_{1} = 1$

$\\ \bf \: \: {\huge{.}} \: \: \: y_{2} = 3$

• Now put the values –

$\\ \implies \bf \: M= \dfrac{3 - 1}{ - 2-8}$

$\\ \implies \bf \: M= - \cancel\dfrac{2}{10}$

$\\ \implies \large{ \boxed{\bf Slope(M)= - \dfrac{1}{5}}}$

• Hence , The Slope is - ⅕ .

$\\ \rule{220}{2}$

✯ ADDITIONAL INFORMATION :–

$\\ \bf (1) \: m = \dfrac{ y_{2} - y_{1}}{x_{2} - x_{1}}$

$\\ \bf (2) \: write \: \: the \: \: given \: \: line \: \: in \: \: y = mx + c \: \: form \\ \sf \: here \: \: m \to \: \: slope$

$\\ \bf (3) \: Point \:\: slope \:\: form \: \: y - y_{1}= m ( x - x_{1})$

Answer 2

Given ,

The two points are (8 , 1) and (-2 , 3)

We know that , the point slope form is given by

$\boxed{ \tt{Slope \: (m) = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1}} }}$

Thus ,

m = (3 - 1)/(-2 - 8)

m = 2/-10

m = -1/5

Therefore , the required slope of line -1/5

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