Question

what is the smallest 4 digit number which when divided by 18 and 18 leaves remainder 8 in each case

Answer 1

Firstly, start with finding the LCM of given two numbers (16 and 18) and that is 144. Now here, according to the question, we need to find a number, which is eight access to the multiple of 144 and it should also be the smallest 4 digit number. Required number = 144x + 8.