Question

what is the smallest 5 digit integer which is divisible by 6 and 10 leaves a remainder of 3​

Answer 1

Answer:

See this is your answer hope it is correct

Answer 2

Answer:

10203

Explanation:

First we need to find least common multiple of 6, 10.

we can solve as l.c.m (6, 10) = 30  so any number which gives us remainder 3 must be in the form of N= 30k + 3 ,for some k integer.

so, k= 30, N= 903 which is three digit number.

Now, for k=32, N=963 which is three digit number.

for k=33, N=1002 which is four digit number.

for k=36, N=1083 which is four digit number.

for k=300, N=9003 which is four digit number.

for k=340, N=10203 which is five digit number.

check : 10203 is divided by 6 and 10 leaves reminder of 3 in each cases. OK