What is the smallest 5 digit number which is exactly divisible by 15, 24 and 40
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Answered by
0
Answer:
120
Step-by-step explanation:
Consider the prime factors:
15 = 3 * 5
24 = 2^3 * 3
40 = 2^3 * 5
The smallest number that is a multiple of all of these would then be:
2^3 * 3 * 5 = 120
The smallest 5-digit number is 10,000 but you need to find the smallest 5-digit that is a multiple of 120.
Dividing 10,000 by 120 gives 83.333…, so the answer must be 84 times 120.
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Answered by
17
What is the smallest 5 digit number which is exactly divisible by 15, 24 and 40.
LCM of 15,24 and 40 is 120
smallest number of five digit =10000
on dividing 10000 by 120 we get remainder 40
Now add (120-40) =80 to the number to make it a number of five digit
required answer will be (10000+80)=10080.
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