what is the smallest coefficient of a number in maths
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Answer:
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Answered by
0
Answer:
Given (x
2
+
x
3
1
)
n
T
r
=
r=0
∑
n
n
C
r
x
2n−2r
.x
−3r
==
r=0
∑
n
n
C
r
x
2n−5r
2n−5r=1⇒2n=5r+1
for r=23
2n=5(23)+1⇒2n=116⇒n=58
Smallest value of n is 58
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