Math, asked by abhijain092000, 4 months ago

What is the smallest digit that should be replaced by * in the number 696*12, to make it divisible by 12
A.O
B. 1
0.2
E None of these​

Answers

Answered by jpmishrarnpur72
0

Answer:

answer is A.O

Step-by-step explanation:

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Answered by RvChaudharY50
1

Solution :-

We know that,

  • When sum of all digits is divisible by 3 , the given number is divisible by 3 .
  • When last two digits of a number is divisible by 4 , the given number is divisible by 4 .
  • When a number is divisible by 3 and 4 both , the given number is also divisible by 12 .

So, checking for 4 :-

→ 696*12 = Last two digits 12 = 12 ÷ 4 = 0 remainder .

since last two digits are divisible by 4 .Therefore 696*12 is divisible by 4 .

checking for 3 :-

→ (6 + 9 + 6 + * + 1 + 2) ÷ 3

→ (24 + * ) ÷ 3

when we put * = 0,

→ (24 + 0) ÷ 3

→ 24 ÷ 3 = Remainder 0 .

As sum of digits is divisible by 3 , the number 696012 is also divisible by 3 .

Therefore, we can conclude that, when 696012 is divisible by 3 and 4 both, it is also divisible by 12 .

Hence, smallest digit that should be replaced by * is equal to 0 .

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