Math, asked by yashkaranradcli4665, 10 months ago

What is the smallest five digit no. Which when divided by 7,11and 21 leaves a remainder of 3 in each case?

Answers

Answered by RvChaudharY50

4

Answer:

LCM of 7,11 and 21 = 231

smallest 5 digit number = 10000

multiple of 231 near 10000 = 10164

so, the required number will be = 10164 +3 = 10167 (Ans.)

[mark as brainlist if you understand my solution]

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