Question

what is the smallest fraction that must be added to 1 whole 1 upon 3 / 1 whole 1 upon 2 divided by 1 whole 1 upon 9 to make the result an integer​

Answer 1

Answer:

1/5

Step-by-step explanation:

let the fraction be x

(1+1/3)

=> x + ------------ ÷ (1+1/9)

(1+1/2)

4/3

=> x+ -------- × 9/10

3/2

4×2×9

=> x+ ------------

3×3×10

4

=> x+----- = integer (5/5)

5

=> x = 5/5 -4/5 = 1/5

=> smallest fraction = 1/5

hope this helps you