Math, asked by Mahica6260, 1 year ago

What is the smallest natural number which when multiplied by 15 and then devided by 63 leaves remainder 21?

Answers

Answered by haridasan85

3

Answer:

(15x-21)/63

x = I,2,3,4 ... 14

(15x14-21)/63

(210-21)/63

I89 / 63=3

so I4 is the smallest natural No

Answered by itzshrutiBasrani

2

Answer:

Step-by-step explanation:

(15x-21)/63

x = I,2,3,4 ... 14

(15x14-21)/63

(210-21)/63

I89 / 63=3

so I4 is the smallest natural No

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