Math, asked by kindness1594, 1 year ago

• what is the smallest no. that when divided by 35,56,91 leaves remainders of 7 in each case?

Answers

Answered by AnjaliRaut
1
Subtract 7 from 35 , 56 and 91 .

Therefore --

35 - 7 = 28 ....................... 1

56 - 7 = 49 ....................... 2

91 - 7 = 84 ........................ 3

So for smallest number we need to find HCF of new numbers

28 = 2 × 2 × 7

49 = 7 × 7

84 = 2 × 2 × 3 × 7

Therefore HCF = 7

So the smallest number is 7 .
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