Question

What is the smallest no which when divide by 35 56 and 91 leave remainder 7in each case

Answer 1

$\sf\underline{Step-by-step \: explanation}$

1) Take out the Lcm of 35 , 56 and 91

7 | 35 , 56 , 91

2. | 5 , 8 , 13

2 | 5 , 4 , 13

| 5 , 2 , 13

Lcm of the numbers = 7 × 2 × 2 × 5 × 2 × 13

》3640

2) Add 7 to the Lcm of the numbers.

¤ 3640 + 7 = 3647

Hence, the number will be,

$\huge\underline{3647}$

Verification :

3647 ÷ 35 = 104 (Remainder = 7)

3647 ÷ 56 = 65 (Remainder = 7)

3647 ÷ 91 = 40 (Remainder = 7)