Question

What is the smallest no. Which when divided by 10 gives remainder of 9 , when divided by 9 give remainder of 8 and so on?

Answer 1

Answer:

Step-by-step explanation : So if we divide the number by 10 then it gives the remainder 9 .So we can assume that the number in the unit place be 9 .

So when we divide it by nine then it gives the remainder 8 . so we can do subtraction . 9 - 8 = 1 . We got the unit digit of division of 9 . In 9 table 81 is the number which has 1 at its units place . So after dividing remainder is 8 . Therefore 81 + 8 = 89 .

Here we got the answer . Lets prove it !

89 ÷ 10 gives remainder 9 .

89 ÷ 9 gives remainder 8 .

Hence our answer is correct .