Question

What is the smallest no which when divided by 5,10,12and 15 leaves remainder 2 in each case but when divided by 7 leaves nothing?

Answer 1

Answer:

LCM of 5,10,12,15 = 60

smallest number that gives remainder 2 is = 62

but it is not divisible by 7,

so we have to check next number .

General term become = (60n+2)

and it should be divisible by 7.

put value of n = 2,3,4,5, _________

n = 2 , = 120+2 = 122 , not divisible by 7

n = 3, = 180+2 = 182 , Divisible by 7 .

so, 182 is the smallest number .

[ mark as brainlist if you understand my solution ]