Question

what is the smallest no which when divuded by 35,56and 91 leaves a remainder of 7in each case

Answer 1

hi. for 35 it's 5, for 56 it's 8, for 91 it's 13.

I hope this helps...

Answer 2

hence 35 ,56 and 91 are the no given
remainder 7 on each case and
(35-7) ,(56-7), (91-7) = the lcm of no
hence after solving get = 7