Question

What is the smallest number by which 2560 must be multiplied to get a perfect cube

Answer 1

Answer:

we try to find by prime factorisation

step by step explaination

$\sqrt[3]{2560 }$

2560=

$2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5$

clearly for making cube must be multiply by

$5 \times 5$

$= 25$

both side

$2560 \times 25 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5 \times 5 \times 5$

hence,

64060=2560 .

ans. = smallest number is 25

Answer 2

Answer:

we try to find by prime factorisation

step by step explaination:-

3√2560

2560=

2×2×2×2×2×2×2×2×2×2×5

clearly for making cube must be multiply by

➡5×5 = 25