Question

what is the smallest number by which 2560 must be multiplied so that the product is the perfect cube ?

Answer 1

Answer:

25

Step-by-step explanation:

Answer 2

Answer:

25

Step-by-step explanation:

Prime factorising 2560, we get,

2560=2⁹×5.

We know, a perfect cube has multiples of 3 as powers of prime factors.

Here, number of 2's is 9 and number of 5's is 1.

So we need to multiply another 5

2

in the factorization to make 2560 a perfect cube.

Hence, the smallest number by which 2560 must be multiplied to obtain a perfect cube is 5

2

=25.