what is the smallest number by which 3922 may be divided so that the product is a perfect cube
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Prime factorising 392, we get,
392=2×2×2×7×7
=2
3
×7
2
.
We know, a perfect cube has multiples of 3 as powers of prime factors.
Here, number of 2's is 3 and number of 7's is 2.
So we need to multiply another 7 to the factorization to make 392 a perfect cube.
Hence, the smallest number by which 392 must be multiplied to obtain a perfect cube is 7.
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