what is the smallest number by which 6912 must be divided so that the quotient obtained will be a perfect cube
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6912=2×2×2×2×2×2×2×2×3×3×3
=2×2×3
=12
But there is two numbers which is ungrouped 2×2=4
So , 4 is the smallest no. which must be divided 6912 so that the quotient obtained will be a perfect cube.
The quotient is perfect cube of 12.
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