Question

what is the smallest number by which 93312 must be multiplied to make a perfect cube

Answer 1

Step-by-step explanation:

Correct option is

A

17

By prime factorising 7803,

we get, 7803=3×3×3×17×17

=33×172

We know, a perfect cube has multiples of 3 as powers of prime factors.

Here, power of 3 is 3 but power of 17 is 2.

So we need to multiply another 17 to the factorization to make 7803 a perfect cube.

Hence, the smallest number by which 7803 must be multiplied to obtain a perfect cube is 17.

Answer 2

Answer:

by 4

Step-by-step explanation:

power of 3 is 6 but that of 2 is 7 to make it a perfect cube it must be multiplied by 2 to the power 2 i.e. 4

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