Question

What is the smallest number by which the following numbers

must be divided so that the quotient is a perfect cube?


5324

​

Answer 1

Answer:

First

find the factors of 5324 by prime factorisation method, then observe that which no. does not forms a triplet. the number that does not forms a triplet is the number by which 5324 must be multiplied to get a perfect cube.

Step-by-step explanation:

5324= 2 x 2 x 11 x 11 x 11

Hence we observe that 2 x 2 is not in the form of a triplet.

Hence 2 x 2= 4.

Now we must divide 5324 by 4.

then we get 5324 ÷ 4= 1331.

$\sqrt[3]{1331} = 11$

hence, 5324 must be divided by 4 to get a perfect cube.

Hope this was helpful..