Question

What is the smallest number of 5 digit which is divisible by 12,15 and 18

Answer 1

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Step 1 : Find L.C.M ( 12 , 15 ,18 )
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12 = 2 × 2 × 3

15 = 3 × 5

18 = 2 × 3 × 3

L.C.M = 2^2 × 5 × 3^2 = 180

since , we know that

smallest 5 digit number = 10000

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Step 2 : Devide 10000 by L.C.M
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10000/180 = 55.5... = 56 (approximate)

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Step 3 : multiply L.C.M by 56 (quotient)
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180 × 56 = 10080

therefore ,

required smallest 5 digit number

= 10080

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Your Answer = 10080
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Answer 2

HI HERE IS THE ANSWER


FIRSTLY WE WILL TAKE LCM OF 12,15,18

LCM =180

5 DIGIT SMALLEST NUMBER =10000

DIVIDE THE 10000 WITH THE LCM
=10000÷180≈55.5

APPROXIMATE 55.5(56)

MULTIPLY APPROXIMATED QUOTIENT WITH 180 TO GET 5 DIGIT SMALLEST NUMBER DIVISIBLE BY 12,15,18
=180×56


= 10080