Question

What is the smallest number of five digits which is divisible by 15, 27 and 35?

Answer 1

For this we need to find the LCM of 15, 27 and 35.

15 = 3 * 5

27 = 3 * 3 * 3 = 3^3

35 = 5 * 7

LCM = 3 * 3 * 3 * 5 * 7 = 3^3 * 5 * 7 = 945.

Therefore the multiples of 945 are divisible by all the three numbers .

To get the five digit number, multiply 945 * 11. (since 9450 * 10 = 9450 = four digit number. multiplying by the next number would give the least five digit number divisible by all three numbers ).

= 945 * 11

= 10395

Hope it helps!!!!!

plz mark as the brainliest answer if its correct......